MongoDB Shell Basics

MongoDB Shell Basics

by John Vincent


Posted on April 14, 2017


Working directly with MongoDB

MongoDB Shell Basics

This article refers to a Thinkful course 2.1.2

MongoDB Shell Basics

Download data

and Import

cd /Users/jv/Downloads
mongoimport --db tempTestDb --collection restaurants --drop --file primer-dataset.json

Databases

Database Commands Documentation

Collection Methods Documentation

Document Validation

Switch to the test database

use tempTestDb

A database is made up of collections, which are in turn made up of documents. A collection holds instances of a single kind of document. A recipes collection would contain individual recipe documents. A users collection would contain individual user documents.

A collection is comparable to a table in a relational database.

List collections:

db.getCollectionNames()

List one document from collection restaurants

db.restaurants.findOne()

Creating Documents

var myRestaurant = {
  address: {},
  borough: "Queens",
  cuisine: "Colombian",
  grades: [],
  name: "Seba Seba",
  restaurant_id: "373737373737373737"
}
db.restaurants.insertOne(myRestaurant);

Also see:

insert()

insertMany()

Querying Documents

find()

Example:

db.restaurants.
  find({borough: "Manhattan"}, {_id: 1, name: 1, address: 1}).
  sort({name: 1}).
  limit(5);

Query Operators

Query by Id

// In all of the remaining examples, any unique
// identifiers are only exemplary. When your Mongo
// server first imports its data, it will automatically
// generate _id values for each document. Use
// `db.restaurants.findOne({})._id;` to get the id of
// an existing object. You can then find by id as below:
var documentId = ObjectId('5840516d2af5143db9cd70c9');
db.restaurants.findOne({_id: documentId});

Updating documents

update()

$set operator

Example:

var objectId = db.restaurants.findOne({}, {_id: 1})._id

db.restaurants.updateOne(
  {_id: objectId},
  {$set: {name: "Foo Bar Bizz Bang"}}
);
// see our changes
db.restaurants.findOne({_id: objectId});

It's also possible to fully replace a document.

db.restaurants.updateOne(
  {_id: objectId},
  {name: "Yummy Yum Yum's"}
);
// this will return a document that ONLY
// has a name property, because if we don't use
// the $set operator and just send an object, Mongo replaces the current document properties with whatever
// we supply in this object.
db.restaurants.findOne({_id: objectId});

Deleting documents

remove()

or .deleteOne or .deleteMany

Example:

var objectId = db.restaurants.findOne({}, {_id: 1})._id
db.restaurants.find({_id: objectId}).count(); // => 1
db.restaurants.remove({_id: objectId});
db.restaurants.find({_id: objectId}).count(); // => 0